A ball of mass 0.150kg is dropped from a height of 1.25m. It rebounds from the floor to reach a height of 0.960m. What impulse was given to the ball by the floor?

Answer 1

Calculate the downward velocity V1 when it hits the floor:
V1 = sqrt (2gH), where H = 1.25 m
Then calculate the upward velocity after the bounce:
V2 = sqrt (2gH'), where H' = 0.96 m
The momentum change is M(V1 + V2), since the V's are in opposite directions.
The momentum change equals the impulse given by the floor.

Answer 2

1.35kgm/s