Max force at bottom = 20 = m v^2/r + m g
20/.25 = v^2/1.2 + 9.81
v^2 = 70.19 *1.2 = 84.2
v = 9.17 m/s
A ball (m = 250g) on the end of
string swings in 1.2 m radius that tolerates 20 N. At what speed does the string breaks if
a) the rings swings horizontally ?
b) the rings swing vertically?
I think I got a) right:
T=mv2/r ---> v=(sqr)Tr/m
v=(sqr) 20x1.2/0.25= 9.8 m/s
Given answers are: 9.8 m/s and 9.2 m/s
Can someone help me how to find maximum speed when the rings swings vertically please ? :)
1 answer
1 answer