A ball is tossed straight up into the air with an initial velocity of +15 m/s and at a height (from where it leaves the thrower's hand) of 2.0 m off the ground. Once the ball leaves the thrower's hand, it accelerates at -9.8m/s/s.

Question

a) How much does it take for the ball to hit the ground?

b) What is the highest position reached by the ball?

c) What is the acceleration of the ball at its highest point?

Answer 1

a) h=hi+vi*time - 4.9 t^2
solve for time
b) divide that time by 2, then figure height, same equation.

c) acceleration everywhere is the same, due to gravity.