A ball is tossed from an upper-story window of a building. The ball is given an initial velocity of 7.50 m/s at an angle of 18.0° below the horizontal. It strikes the ground 5.00 s later.

(a) How far horizontally from the base of the building does the ball strike the ground?
m

(b) Find the height from which the ball was thrown.
m

(c) How long does it take the ball to reach a point 10.0 m below the level of launching?
s

1 answer

vertical component.
hf=hi+vi'*t-4.9t^2
hf=0, vi'=-7.5sin18, t=5, solve for hi
horizontal distance:
distance=vi*cos18*timeinair

for the c), same formula as above, solve for t given hf=-10