1) v = vo + at
v = 40 - 9.8*3
2) x = v^2/(2*9.8)
t = vo/t
3) t = twice the max height time.
A ball is thrown vertically upword with an initial velocity of 40m/s (1) calculate 1 it velocity after 3secs (2) the maximum height attend and the time taken to reach the maximum height (3) the total taken for the ball to return to the grand again
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