a. h = (Vf^2-Vo^2)/2g.
h = (0-361)/-19.6 = 18.4 m.
b. Tr = (Vf-Vo)/g.
Tr = (0-19)/-9.8 = 1.94 s. = Rise time.
c. Tf = Tr = 1.94 s. = Fall time.
OR
0 + 4.9*t^2 = 18.4.
t^2 = 3.755
Tf = 1.94 s. = Fall time.
d. Vf = Vo + gt = 0 + 4.9*1.94=19 m/s.
A ball is thrown vertically upward with a speed of 19.0 m/s.
(a) How high does it rise?
m
(b) How long does it take to reach its highest point?
s
(c) How long does the ball take to hit the ground after it reaches its highest point?
s
(d) What is its velocity when it returns to the level from which it started?
m/s
1 answer
1 answer