1. V = Vo + g*t, g = -9.8 m/s^2.
2. a = g = -9.8 m/s^2.
3. V = Vo + g*Tr, V = 0, Vo = 70 m/s, g = -9.8 m/s^2, Tr = Rise time, Solve for Tr.
4. Tf = Fall time, T = Tr+Tf,
Tf = Tr, T = Tr+Tr = 2Tr = Time
required to reach gnd.
5. V^2 = Vo^2 + 2g*h = 0,
h = -(Vo^2)/2g, g = -9.8 m/s^2,
Vo = 70 m/s,
A ball is thrown upwards with an initial velocity of 70 m/s
1. What is the velocity after 3 seconds?
2. What is the acceleration at the top of its path?
3. How many seconds does it take the ball to go up?
4. How many seconds does it take to hit the ground?
5. How high does the ball go?
1 answer