a ball is thrown upwards on the moon with an initial speed of 35m/s .calculate a.time taken to reach the maximum height . b. the maximum height reached by the ball . c. its velocity 3 seconds after it has been thrown.
2 answers
please help me solve this
find g on the moon. Using that value,
since v = 35-gt, max height, achieved when v=0, is when t = 35/g
h(t) = 35 - 1/2 gt^2
find h(3)
since v = 35-gt, max height, achieved when v=0, is when t = 35/g
h(t) = 35 - 1/2 gt^2
find h(3)