A ball is thrown upwards and reaches the ground once again after 4 sec: (a)calculate the height that the ball reaches (b)the total distance covered by the ball (c)the velocity with which the ball hits the ground

Answer 1

h(t)=h(0)+vi*t-1/2 g t^2
0=0+vi*4-4.9(4^2)
so you need the initial velocity, vi, or vi=4.9*4 m/s.
height: vi*2
distance: 2*vi*2
vf=-vi

Answer 2

Height=364.56m