A ball is thrown upward with an initial velocity of 18.5 meters per second from an initial height of 22.5 meters.(assume acceleration is -9.8 m/s (1.find the position function giving the height us as a function of time T)(2. when does the ball hit the ground?)

Answer 1

the ball hits the ground when h=0
as before,
h(t) = -4.9t^2 + 18.5t + 22.5
so solve as usual.