A ball is thrown upward from the top of a 35-m tower, with initial velocity of 80m/s at an angle of 25 (a) find the time to reach the ground and the distance from the base of the tower to the point of impact (b) find the magnitude and direction of the velocity at the moment of impact.

Answer 1

the initial upward velocity is 80 sin 25° = 33.8 m/s

So, the height

y = 35 + 33.8t - 4.9t^2
(a) t = 7.8
So, use that to find the horizontal distance traveled at 80 cos25° = 72.5 m/s

Finally, find the x- and y-components of the velocity at t=7.8 to get the answers to (b)