A ball is thrown upward from the top of a 24.4-m-tall building. The ball's initial speed is 12 m/s. At the same instant, a person is running on the ground at a distance of 30.2 m from the building. What must be the average speed of the person if he is to catch the ball at the bottom of the building?

Question

A ball is thrown upward from the top of a 24.4-m-tall building. The ball's initial speed is 12 m/s. At the same instant, a person is running on the ground at a distance of 30.2 m from the building. What must be the average speed of the person if he is to catch the ball at the bottom of the building?
PLEASE HELP!!!!!!! :)

bobpursley · Answer

find the time it takes the ball to get to the bottom Hf=hi+vi*t-1/2 g t^2 0=24.4+12*t-4.8 t^2 use the quadratic equation to find time of fall t. Now, how fast does the person run? v=30.2/timet