a ball is thrown upward from a bridge with a speed of 48 ft/s. It misses the bridge on way down and lands in water 160 ft. below. Find how long the ball rises, how high it goes, how long it is in the air, and its velocity when it strikes the water.

Answer 1

just start with the usual functions for height and velocity, and then solve for the values you need

v = 48-16t
s = 160+48t-8t^2

assuming the water is at height 0.