A ball is thrown upward at a speed v0 at an angle of 57.0˚ above the horizontal. It reaches a maximum height of 7.4 m. How high would this ball go if it were thrown straight upward at speed v0?

Answer 1

Vo[57o],
Yo = Vo*sin57. = Ver. component of Vo.

Y^2 = Yo^2 + 2g*h = 0,
Yo^2 + (-19.6)7.4 = 0,
Yo = 12.04 m/s.

Yo = Vo*sin57 = 12.04,
Vo = 14.36 m/s.

V^2 = Vo^2 + 2g*h = 0,
14.36^2 + (-19.6)h = 0,
h = 10.5 m.