A ball is thrown upward at a speed v0 at an angle of 52.0˚ above the horizontal. It reaches a maximum height of 7.3 m. How high would this ball go if it were thrown straight upward at speed v0?

Answer 1

The height is rises is proportional to (Vo*sinA)^2
Only the vertical component of velocity can be exchanged for gravitational potential energy.

Vo stays the same

The height ratio is therefore

H(90deg)/H(52deg) = (sin90/sin52)^2 = 1.610

H(90 deg) = 1.610*7.3 = 11.76 m

Answer 2

A ball is thrown upward at a speed v0 at an angle of 56.0˚ above the horizontal. It reaches a maximum height of 6.9 m. How high would this ball go if it were thrown straight upward at speed v0?