A ball is thrown up from a twelve foot platform with an initial velocity of 112 feet/second. The formula that describes the height of the ball in terms of time is: f(t) = -16t^2+112t+12.

Question

Determine the time at which the ball reaches its maximum height. Determine the maximum height of the ball.

Answer 1

f'(t) = -32t + 112
= 0 for a max of f(t)
32t = 112
t = 3.5

then f(3.5) = -16(3.5^2) + 112(3.5) + 12
= 208