the horizontal velocity is
... 31 m/s * cos(60º)
the vertical velocity is
... 31 m/s * sin(60º) +
... 3.4 s * -9.8 m/s^2
add the two component vectors
... a^2 + b^2 = c^2
A ball is thrown toward a cliff of height h with a speed of 31 m/s and an angle of 60∘ above horizontal. It lands on the edge of the cliff 3.4 s later.
What is the ball's impact speed?
1 answer