A ball is thrown straight up from the top of a building 144 ft tall with an initial velocity of 48 ft per second. The height
s(t) (in feet)
of the ball from the ground, at time t (in seconds), is given by
s(t) = 144 + 48t − 16t2.
Find the maximum height attained by the ball.
1 answer
as with all quadratics (ax^2+bx+c), the vertex is at x = -b/2a
2 answers