max height is on the axis of symmetry of the parabola ... x = -b / (2a)
tmax = -80 / (2 * -16) = 2.5 s
plug the time into the height equation to find max height
A ball is thrown straight up from the top of a building 128 ft tall with an initial velocity of 80 ft per second. The height
s(t) (in feet)
of the ball from the ground, at time t (in seconds), is given by
s(t) = 128 + 80t − 16t^2.
Find the maximum height attained by the ball
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