A ball is thrown straight up from the top of a 200 foot building with an initial velocity of 40feet/second. acceleration due to gravity is -32feet/second.

Question

a) find a formula for the height of the ball at time t.

b) how high does the ball rise before it begins to fall

c) when does it hit the ground(assuming it does not fall back onto the roof of the building)

Answer 1

h(t) = 200 + 40t - 16t^2

now work your magic on (b) and (c)