v(t)=v(o)+gt g=-9.8m/s^2, v(o)=-.5m/s
I frankly would also verify that the ball had not hit the ground in this time, sometimes these question are tricks.
A ball is thrown straight downward with a speed of 0.50 meter per second from a height of 4.0 meters. What is the speed of the ball 0.70 second after it is released?
2 answers
That was good advice from BobPursley.
After 0.7s, the ball will have travelled 2.75 meters down, so it will not have hit the ground yet.
If it had hit the ground, you would need a "turnaround time" (probably very short) and "coefficient of restitution" to get the velocity.
After 0.7s, the ball will have travelled 2.75 meters down, so it will not have hit the ground yet.
If it had hit the ground, you would need a "turnaround time" (probably very short) and "coefficient of restitution" to get the velocity.