A ball is thrown so that the motion is defined by the equations x= 5t and y= 2+6t-4.9t^2, where x and y are expressed in meters and t is expressed in seconds. Determine (a) the velocity at t=1s, (b) the horizontal distance the ball travels before hitting the ground

Answer 1

the velocity is constant in the x-direction ... dx/dt = 5 m/s

the velocity in the y-direction is time dependent ... dy/dt = 6 - 9.8 t m/s

(a) plug in t = 1 , and add the x and y velocity vectors

(b) set y=0 and solve for t , plug the result into the x equation

Answer 2

a. 5.88 m/s

b. 7.5 m