A ball is thrown into the air with an upward velocity of 36ft/s. It’s height h in feet after t seconds is given by the function h=-16t^2+36t+9

1 answer

To find the height of the ball after a certain time, substitute the given time into the equation h = -16t^2 + 36t + 9.

For example, to find the height after 2 seconds, substitute t = 2:

h = -16(2)^2 + 36(2) + 9
h = -16(4) + 72 + 9
h = -64 + 72 + 9
h = 17 feet

Therefore, after 2 seconds, the height of the ball is 17 feet.