The height of the ball in feet after t seconds is given by the function:
h(t) = -16t^2 + 46t
To determine when the ball will hit the ground, we need to find the time when the height is equal to 0. In other words, we need to solve the equation:
-16t^2 + 46t = 0
Factor out a t from the equation:
t(-16t + 46) = 0
Set each factor to 0:
t = 0 or -16t + 46 = 0
If t = 0, the ball is at the ground initially.
For -16t + 46 = 0:
-16t + 46 = 0
-16t = -46
t = 46/16
t = 23/8
t = 2.875
Therefore, the ball will hit the ground after approximately 2.875 seconds.
The closest response would be 3 seconds.
A ball is thrown into the air with an initial upward velocity of 46 ft/s. Its height (h) in feet after t seconds is given by the function . After how many seconds will the ball hit the ground? (1 point) Responses 3 4 5 6
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