V^2 = Vo^2 + 2g*h
V^2 = 0 + 19.6*150 = 2,940
V = 54.2 m/s.
A ball is thrown horizontally from the top of a building 150 meters high. The ball strikes the ground 56 meters horizontally from the point of release. What is the speed of the ball just before it strikes the ground?
1 answer