A ball is thrown horizontally from the top of

a building 130 m high. The ball strikes the
ground 70 m horizontally from the point of
release.
What is the speed of the ball just before it
strikes the ground?
Answer in units of m/s.

1 answer

V^2 = Vo^2 + 2g*h. = 0 + 19.6*130 = 2548,
V =