A ball is thrown from the top of a 50-ft building

with an upward velocity of 24 ft/s. When will it
reach its maximum height? How far above the
ground will it be? Use the equation
h(t)= -16t^2 + 24t + 50

1 answer

a. V = Vo + g*t = 0.
24 + (-32)t = 0,
t = 0.75 s.

b. Use your given Eq to find ht.