you want to evaluate y(100). That is the height of the ball when it hits the wall
h(m) = y(100) = 100m-{(e^2m)/10}
So, where is that a maximum?
h' = 100 - e^(2m)/5
Where is h' = 0?
A Ball is thrown from the origin of a coordinate system. The equation of its path is y=mx-{(e^2m)x^2/1000}, where m is positive and represents the slope of the path of the ball at the origin.
For what value of m will the ball strike at the greatest height on a verticle wall located 100 feet from the origin?
1 answer