(a) Maximum height H is where
g*H = (Vo*sin32)^2/2
(b) Vo*cos35, which remains constant while the vertical velocity component becomes zero at max height.
A ball is thrown from a point 1.1 m above the ground. The initial velocity is 20.3 m/s at an angle of 32.0° above the horizontal.
(a) Find the maximum height of the ball above the ground???
(b) Calculate the speed of the ball at the highest point in the trajectory???
2 answers
What would the Vo be???
0 or 20.3???
0 or 20.3???
3 answers