a ball is thrown downward from the too of 110 ft bldg with an initial velocity of 14ft per second. the height of ball h after t seconds is given by the equation h = -16t^2-14t +110.

Question

how long after ball is thrown will it hit the ground

Answer 1

when it is at ground level , h = 0
16t^2 + 14t - 110=0
8t^2 + 7t - 55 = 0
t = (-7 ± √1809)/16 = 2.22 or a negative

so it took 2.22 seconds before it hit the ground