A ball is thrown directly upward from the ground with an initial velocity of 4.8 ft./sec. Represent the height of the ball from the ground t seconds after it was thrown upward using the model h(t).(1 point)

Question

h(t)=−1/2*4.8t^2+4.8t

h(t)=−1/2*32t^2+4.8t+4.8

h(t)=−16t2+4.8t

h(t)=−1/2*9.8t^2+4.8t

Answer 1

The correct answer is: h(t) = -16t^2 + 4.8t