constant horizontal speed = 22 cos 45
so time to fence = t = 100 /(22 cos 45)
so how high is it at time t?
h = initial height assume 0 + [ 22 sin 45] t - (1/2)(9.81) t^2
That gives you h in meters. Convert to feet to see if it is higher than five feet.
A ball is thrown at 22m/s at 45 degrees to the horizontal. a fence 5 feet tall is located 100 meters away. Does the ball make it over the fence?
1 answer
1 answer