A ball is thrown 60m vertically into the air. What was its initial velocity? How much time does it take to reach the highest point?

1 answer

at the top, its PE = mgh
when thrown, that was all KE = 1/2 mv^2
so, v^2 = 2gh
now, having v, and knowing that velocity is zero at the top, find the time t, using
v - gt = 0