A ball is rolled off a table that is 0.481 m above the floor. The ball is rolling with a velocity if 1.8 m/s as it goes off the edge of the table. At the exact instant the first ball rolls off the table a second ball is dropped from the same height.

Question

A ball is rolled off a table that is 0.481 m above the floor.  The ball is rolling with a velocity if 1.8 m/s as it goes off the edge of the table.  At the exact instant the first ball rolls off the table a second ball is dropped from the same height.
A.) How long does it take each ball to reach the ground?
B.)  What is the velocity of each ball the instant before it hits the ground?

Looking for the answer and the work that provided the correct answer.  Thank you so much!!

Henry · Accepted Answer

A. h = Vo*t + 0.5g*t^2 = 0.481 m. 0 + 4.9t^2 = 0.481 t^2 = 0.09816 t = 0.313 s. Each ball. B. V = Vo + g*t V = 0 + 9.8*0.313 = 3.07 m/s. Each ball.