A ball is released from a hot air balloon moving downward with a velocity of

-10.0 meters/second and a height of 1,000 meters. How long did it take the ball to reach the surface of Earth? Given: g = -9.8 meters/second2.

3 answers

h= v₀t + gt²/2
gt²+2v₀t-2•h = 0
9.8t²+2•10t- 2000=0
t=[20±sqrt{400+4•9.8•1000}]/2•9.8 =
=(20±199)/19.6 =>
t=11.2 s.
lol
its 11.2s
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