A ball is projected with initial velocity 50m\s at an angle of elevation of 37°from the top of a cliff 55m high. calculate the total time the ball is in the air and the maximum horizontal distance covered...please I have solved this question but didn't get the answer ..I need ur assistance..

Answer 1

the initial vertical velocity is
... 50 m/s * sin(37º)

the (vertical) freefall equation is
. h = 1/2 g t^2 + [50 sin(37º)] t + 55

plug in zero for h (ball on ground) and solve for t (use quadratic formula)

the horizontal velocity is
... 50 m/s * cos(37º)
... multiply by t to find distance

remember...g is negative (downward)

Answer 2

It is not good