you omitted it, but if the initial velocity is v0, then the height and velocity at time t are
h(t) = v0*t - 4.9t^2
v(t) = v0 - 9.8t
You left out several words, but with the above equations, you should be answer whatever questions were asked.
A ball is projected upward at time t = 0 s, from a point on a flat roof 10 m above the ground. The ball rises and then falls with insignificant air resistance, missing the roof, and strikes the ground. The initial velocity of the ball is Consider all quantities as positive in the upward direction. At time the vertical velocity of the ball is closest to
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