1) To find the time taken to get to the ground, we can use the equation:
h = 0.5 * g * t^2
where h is the height of the cliff (40m), g is the acceleration due to gravity (9.81m/s^2), and t is the time taken.
Plugging in the values:
40 = 0.5 * 9.81 * t^2
t^2 = 40 / (0.5 * 9.81)
t^2 = 8.15
t = √8.15
t ≈ 2.86 seconds
2) The vertical component of the velocity on getting to the ground can be found using the equation:
v = g * t
where v is the vertical component of the velocity and t is the time taken (2.86 seconds).
Plugging in the values:
v = 9.81 * 2.86
v ≈ 27.98 m/s
Therefore, the time taken to get to the ground is approximately 2.86 seconds and the vertical component of the velocity on getting to the ground is approximately 27.98 m/s.
A ball is projected horizontally from the top of a vertical cliff 40m high at a velocity of 20ms-¹
1) time taken to get to the ground
2) the vertical component of the velocity on getting to the ground.
1 answer