A ball is projected horizontally from the edge of a table that is 1.00 m high, and it strikes the floor at a point 1.30 m from the base of the table.

(a) What is the initial speed of the ball?
m/s
(b) How high is the ball above the floor when its velocity vector makes a 45.0° angle with the horizontal?
m

2 answers

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How long does it take to fall 1.00 m?
4.9t^2 = 1
t = 0.45s
(a) 1.3m/0.45s = 2.88 m/s
(b) 2.88 = 9.8t
t = 0.29
h = 1 - 4.9*0.29^2 = 0.58 m
Thank you so much this really helped