a ball is launched from the top of a 23 m high cliff with a velocity of 33 m/s oriented 12 degrees above the horizonal. Determine the time it takes for the ball to hit the ground.

Answer 1

the vertical launch velocity is
... 33 sin(12º)

0 = 1/2 g t² + [33 sin(12º)] t + 23

use the quadratic formula to find t
...you want the positive solution

g = 9.8 m/s²