A ball is kicked 30º above the horizontal with an initial velocity of 20m/s. A fence 2.3 meters high is located 32 meters away.
a. How long does it take to reach the fence?
b. Does it goes over the fence? Does it hit the ground before? By how much?
I believe I have to solve the initial Vsub0x and Vsub0y by using sin and cos. Then use the equation v^2=vsub0^2 + 2a (y-ysub0). Then once velocity is solved use the negative value of that to solve for time in the equation v = vsub0 + at, but I don't understand what values I am supposed to use for ysub0 and y in part b because i don't know the time or distance that the ball reaches the ground.
1 answer
the trajectory article at wikipedia gives a good discussion of this kind of problem.