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A ball is hit from the ground. When the ball has traveled a horizontal distance of d meters, its height, h, in meters, can be m...Asked by Noel
                A ball is hit from the ground. When the ball has traveled a horizontal distance of d meters, its height, h, in meters, can be modeled by the function h(d) = 1/125d^2 + d
What is the horizontal distance from the point where the ball is hit to the point where the ball lands on the ground?
            
        What is the horizontal distance from the point where the ball is hit to the point where the ball lands on the ground?
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    When the ball lands on the ground, its height will be 0. We can set h(d) = 0 and solve for d:
0 = 1/125d^2 + d
Multiplying both sides by 125d^2, we get:
0 = d^2 + 125d
Now we can use the zero product property and set each factor equal to zero:
d^2 = 0 or d + 125 = 0
The first solution d = 0 doesn't make sense in this context because it would mean the ball didn't travel any distance horizontally. Therefore, we use the second solution:
d + 125 = 0
d = -125
This negative value doesn't make sense either, so we conclude that the ball lands on the ground at a horizontal distance of 125 meters from where it was hit.
    
0 = 1/125d^2 + d
Multiplying both sides by 125d^2, we get:
0 = d^2 + 125d
Now we can use the zero product property and set each factor equal to zero:
d^2 = 0 or d + 125 = 0
The first solution d = 0 doesn't make sense in this context because it would mean the ball didn't travel any distance horizontally. Therefore, we use the second solution:
d + 125 = 0
d = -125
This negative value doesn't make sense either, so we conclude that the ball lands on the ground at a horizontal distance of 125 meters from where it was hit.
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