A ball is fired from a height of 3.0 m above the ground,with a speed of 13 m/s and an angle of 22 degrees below the horizontal.(a) At what time does the ball hit the ground? (b) What is the impact velocity?

Answer 1

break the initial velocity into vertical and horiontal components.
Then use the vertical velocity in the distance equation..
3=Vvo*time - 4.9time^2 to solve for time.
Impact velocity will be the Vector sum of the initial vertical velocity and the final vertical velocity..
final velocityvertical=initialVv-g*t

Answer 2

Thanks

Answer 3

Mvi-mvf