A ball is dropped vertically from height of 30 meters after bounces.The ball reaches a max height to 60% of height of the previous bounce. What are the terms of the sequence. What is the height to the nearest tenth of a meter of the ball after the tenth bounces?

Answer 1

h0 = 30
h1 = .6*30
h2 = .6^22 * 30
h3= .6^3*30

hn = .6^n*30

h10 = .6^10 * 30 = .2

Answer 2

This is a geometric progression

a1=30
r=.6

What is 30(.6)^10 ?

Answer 3

use the formula sn=(a1)(1-r^n)/(1-r).
a1=30
r=0.60
n=10

Viola :)