During fall, it is under the influence of gravity
d=4.9 t^2 where t is the time it fell.
t= sqrt d/4.9
not sound has to go back up.
d=345*t1 where t1 is the time back up.
but you ARE given t+t1=43 seconds (deep well)
so,
43=t+t1=d/343 + sqrt (d/4.9)
solve this quadratic equation for d Hint, let d= 4.9^2 x^2
A ball is dropped into a well. A splash is heard 43 seconds later. The speed of sound (the speed at which sound travels through the air) is 345 m/s.
HOW DEEP WAS THE WELL?
I don't even know which equation to plug this into. At first I just tried s=d/t-> 345=d/43, but that gave me a value that was too big/ incorrect. What should I do?
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