A ball is dropped from the top of a building. If it takes 3.00 s for the ball to hit the street below, how high is the building?

Answer 1

vf = 0
t = 3.00
a = -g
y = ?

y = vft - 1/2at^2
y = 0 - 1/2(-9.80)(3.00)^2
y = 4.40(9.00)
y = 39.6 m

the building is 39.6 m high

Answer 2

44.1 m was the correct answer