A ball is dropped from the top of a 95 m building. With what speed does the ball hit the ground?

Answer 1

The kinetic energy when it hits the ground equals the initial potential energy.

M*g*H = (1/2)MV^2

V = sqrt(2 g H)

H is the initial height and g is the acceleration of gravity.

Aerodynamic friction has been neglected. The true velocity will be slightly less