A ball is dropped from the same height, but 20

feet away from the side of the building. The height y of the
ball at time t is given by y(t) = 64 − 16t2. How fast is the
shadow of the ball moving along the ground after 1 second?

1 answer

The velocity of the ball after time t is given by:
y'(t)=-32t

The shadow cannot be traced unless the position of the sun or light source is known.