a ball is dropped from height of tower 300m .after 1s another ball is dropped with 20m/s from tower .when and where they meet?

Answer 1

first ball: h=300-1/2 g t^2
second ball: h= 300-20(t-1)-1/2 g (t-1)^2

set the two equations equal, and solve for t. THat is when

put t into either equation to find where.