A ball is dropped from an upper floor, some unknown distance above your apartment. As you look out of your window, which is 1.5 m tall, you observe that it takes the ball 0.18 seconds to traverse the length of the window. Determine how high above the top of your window the ball was dropped. Ignore air resistance.

Answer 1

h = Vo*t + 0.5g*t^2 = 1.5 m.
Vo*0.18 + 4.9*0.18^2 = 1.5
0.18Vo + 0.159 = 1.5
0.18Vo = 1.5 - 0.159 = 1.34
Vo = 7.45 m/s = Initial velocity at top
of window.

V^2 = Vo^2 + 2g*h = 7.45^2
0 + 19.6*h = 55.5
h = 2.83 m. Above the window.